16t^2=192

Solution for 16t^2=192 equation:

16t^2=192

We move all terms to the left:

16t^2-(192)=0

a = 16; b = 0; c = -192;
Δ = b2-4ac
Δ = 02-4·16·(-192)
Δ = 12288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12288}=\sqrt{4096*3}=\sqrt{4096}*\sqrt{3}=64\sqrt{3}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{3}}{2*16}=\frac{0-64\sqrt{3}}{32}
=-\frac{64\sqrt{3}}{32}
=-2\sqrt{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{3}}{2*16}=\frac{0+64\sqrt{3}}{32}
=\frac{64\sqrt{3}}{32}
=2\sqrt{3}
$